Two cars P and Q start from a point at the same time in a straight line and their positions are represented by xP(t)= at+bt2 and xQ(t)= ft-t2. At what time do the cars have the same velocity
Given, xP(t) = at + bt2 and xQ(t) = ft - t2
Hence vP(t) = a+2bt and vQ(t) = f -2t
As vp=vQ, a+2bt = f - 2t.
Therefore .