First slide
Instantaneous velocity
Question

Two cars P and Q start from a point at the same time in a straight line and their positions are represented by xP(t)= at+bt2 and xQ(t)= ft-t2. At what time do the cars have the same velocity

Moderate
Solution

Given, xP(t) = at + bt2  and  xQ(t) = ft - t2
Hence vP(t) = a+2bt  and  vQ(t) = f -2t
As vp=vQ,  a+2bt = f - 2t. 

Therefore  t=f-a21+b.

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