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Q.

Two cells of emf 3V & 5V and internal resistance r1 & r2 respectively are in series with an external resistance R. If the p.d across 2nd cell is zero, then R is

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a

r1-r2

b

r1+r22

c

5r1-3r22

d

3r2-5r15

answer is D.

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Detailed Solution

Total emf in the circuit 5+3 = 8V   total resistance in the circuit r1+r2+R current in the circuit 8r1+r2+RPotential difference across the second cell  5-8r2r1+r2+R=05r1+5r2+5R=8r2 R=3r2-5r15
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