First slide

potentiometer

Question

Two cells of emfs $E_{1}$ and $E_{2}$ are connected as shown in figure $(E_{1} > E_{2})$ , when a potentiometer is connected between A and B, balancing length of the potentiometer wire is 300 cm. On connecting the same potentiometer between A and C, the balancing length is 100 cm. The ratio $E_{1} / E_{2}$ is

Moderate

A

4/3
B

2/3
C

3/2
D

3/4

Solution

$\frac{E_{1}}{E_{1} - E_{2}} = \frac{300}{100} \Rightarrow 2 E_{1} = 3 E_{2} \Rightarrow \frac{E_{1}}{E_{2}} = \frac{3}{2}$

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