Questions
Two cells of the same e.m.f. e but different internal resistances,R1 and R2, are connected in series with an external resistance R. The potential drop across the first cell is found to be zero. The external resistance R [Fig.] is
detailed solution
Correct option is A
Current i in the circuit=2e/r1+r2+RVoltage drop across Ist cell=V1=e−ir1∴ V1=e−2er1R+r1+r2=0∴ e=2er1R+r1+r2 or R+r1+r2=2r1R=r1−r2Talk to our academic expert!
Similar Questions
In the given circuit, the voltmeter records 5 volt. The resistance of the voltmeter in ohms is
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