First slide

potentiometer

Question

Two cells when connected in series are balanced on 8 m on a potentiometer. If the cells are connected with polarities of one of the cells is reversed, they balance on 2 m. The ratio of e.m.f.'s of the two cells is

Easy

A

3 : 5
B

5 : 3
C

3 : 4
D

4 : 3

Solution

$\frac{E_{1}}{E_{2}} = \frac{l_{1} + l_{2}}{l_{1} - l_{2}} = \frac{(8 + 2)}{(8 - 2)} = \frac{5}{3}$

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