Two charges +3.2×10−19 and −3.2×10−19C placed at 2.4Aο apart form an electric dipole. It is placed in a uniform electric field of intensity 4×105 volt/m. The electric dipole moment is
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a
15.36×10−29 coulomb×m
b
15.36×10−19 coulomb×m
c
7.68×10−29 coulomb×m
d
7.68×10−19 coulomb×m
answer is C.
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Detailed Solution
Dipole moment p = q (2l) =3.2×10−19×(2.4×10−10)=7.68×10−29C-m