Two charges +3.2×10−19 and −3.2×10−19C placed at 2.4Aο apart form an electric dipole. It is placed in a uniform electric field of intensity 4×105 volt/m. The electric dipole moment is

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15.36×10−29 coulomb×m

15.36×10−19 coulomb×m

7.68×10−29 coulomb×m

7.68×10−19 coulomb×m

answer is C.

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Detailed Solution

Dipole moment p = q (2l) =3.2×10−19×(2.4×10−10)=7.68×10−29C-m

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