Two charges +3.2×10−19C and −3.2×10−9C kept 2.4 Ao apart forms a dipole. If it is kept in uniform electric field of intensity 4×105volt/m then what will be its electrical energy in equilibrium
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a
+3×10−23 J
b
−3×10−23 J
c
−6×10−23 J
d
−2×10−23 J
answer is B.
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Detailed Solution
Potential energy of electric dipoleU=−pEcosθ=−(q×2l)EcosθU=−3.2×10−19×2.4×10−104×105cosθU=−3×10−23 (approx.)