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Q.

Two charges +3.2×10−19C  and −3.2×10−19C  kept  2.4A0 apart forms a dipole. If it is kept in uniform electric field of intensity  4×105 volt/m then what will be its electrical energy in stable  equilibrium

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a

+3×10−23 J

b

−3×10−23 J

c

−6×10−23 J

d

−1.5×10−23 J

answer is B.

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Detailed Solution

Potential energy of electric dipoleU=−pEcosθ=−q×2lEcosθ  ⇒In stable equilibrium,θ = 0o  & cosθ = 1 ⇒U=−3.2×10−19×2.4×10−104×105 ⇒U=−3×10−23 (approx.).
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