Two charges +5μC and +10μC are placed 20 cm apart. The net electric field at the mid-Point between the two charges is
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a
4.5×106 N/C directed towards +5μC
b
4.5×106 N/C directed towards +10μC
c
13.5×106 N/C directed towards +5μC
d
13.5×106 N/C directed towards +10μC
answer is A.
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Detailed Solution
From following figure, EA= Electric field at mid point M due to +5μC charge =9×109×5×10−6(0.1)2=45×105N/CEB= Electric field at M due to +10μC charge =9×109×10×10−6(0.1)2=90×105N/CNet electric field at M=E→B−E→A=45×105N/C=4.5×106N/C,in the direction of EB i.e.towards +5μC charge