First slide

Electric field

Question

Two charges +4e and +e are at a distance x apart. The distance, a charge q must be placed from charge +e so that it is in equilibrium, is $nx$ . The value of $n$ is

Easy

Solution

For equilibrium of q
$|F_{1}| = |F_{2}|$
Which gives $x_{2} = \frac{x}{\sqrt{\frac{Q_{1}}{Q_{2}}} + 1} = \frac{x}{\sqrt{\frac{4 e}{e}} + 1} = \frac{x}{3}$

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