First slide

Electrostatic force

Question

Two charges of equal magnitudes and at a distance r exert a force F on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is

Easy

A

F / 8
B

F / 4
C

4 F
D

F / 16

Solution

$F = k \cdot \frac{Q^{2}}{r^{2}}$ . If Q is halved, r is doubled then
$F \to \frac{1}{16} times$

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