Two charges of equal magnitudes and at a distance r exert a force F on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is
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a
F / 8
b
F / 4
c
4 F
d
F / 16
answer is D.
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Detailed Solution
F=k⋅Q2r2. If Q is halved, r is doubled then F→116 times
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Two charges of equal magnitudes and at a distance r exert a force F on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is