Two charges of equal magnitudes and at a distance r exert a force F on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is

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F / 8

F / 4

4 F

F / 16

answer is D.

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Detailed Solution

F=k⋅Q2r2. If Q is halved, r is doubled then F→116 times

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