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Q.

Two charges Q1 = 18 μC and Q2 = -2 μC are separated by a distance R, and Q1 is on the left of Q2. The distance of the point where the net electric field is zero is

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a

between Q1 and Q2

b

left of Q1 at R/2

c

right of Q2 at R

d

right of Q2 at R/2

answer is D.

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Detailed Solution

Neutral point is obtained at point P located at distance x on right of Q2∴kQ2x2=kQ1(x+R)2 put Q2=2μC and Q1=18μC ⇒x+Rx=3 ⇒ x=R2OR ⇒x=dq2q1-1=R182-1=R2

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