Two charges Q1 and Q2 are distance d apart. Two dielectrics of thickness t1 and t2 and dielectric constant k1 and k2 are introduced as shown. Find the force between the charges
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
Q1Q24πε0d−t1+t2+k1t1+k2t22
b
zero
c
Q1Q24πε0d+k1t1+k2t22
d
Q1Q24πε0k1−1t1+k2−1t2+d2
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Effective distance in vacuum is given byr=t1K1+t2K2+d-t1+t2 so, F=Q1Q24πε0t1K1+t2K2+d-t1-t22 ⇒F =Q1Q24πε0K1-1t1+K2-1t2+d2
Two charges Q1 and Q2 are distance d apart. Two dielectrics of thickness t1 and t2 and dielectric constant k1 and k2 are introduced as shown. Find the force between the charges