Two charges +3.2×10-19 and -3.2x10-19 C placed at 2.4A apart form an electric dipole. It is placed in a uniform electric field of intensity 4 × 105 V/m . The electric dipole moment is
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a
15.36×10-29Cm
b
15.36×10-19Cm
c
7.68×10-29Cm
d
7.68×10-19Cm
answer is C.
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Detailed Solution
Dipole moment, p = q (2l)=3.2×10-19×2.4×10-10=7.68×10-29C-m