Q.

Two charges +3.2×10-19 and -3.2x10-19 C placed at 2.4A apart form an electric dipole. It is placed in a uniform electric field of intensity 4 × 105 V/m . The electric dipole moment is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

15.36×10-29Cm

b

15.36×10-19Cm

c

7.68×10-29Cm

d

7.68×10-19Cm

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Dipole moment, p = q (2l)=3.2×10-19×2.4×10-10=7.68×10-29C-m
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
Two charges +3.2×10-19 and -3.2x10-19 C placed at 2.4A apart form an electric dipole. It is placed in a uniform electric field of intensity 4 × 105 V/m . The electric dipole moment is