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Q.

Two circuits have coefficient of mutual induction of 0.09 henry. Average e.m.f. induced in the secondary by a change of current from 0 to 20 ampere in 0.006 second in the primary will be

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a

120 V

b

80 V

c

200 V

d

300 V

answer is D.

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Detailed Solution

e=Mdidt=0.09×200.006=300 V
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