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Q.

Two circular coils A and B having number of turns 3N and N respectively and carrying equal currents in same sense are placed coaxially, such that they subtend the same solid angle at O. Let B0 be the magnetic field at O due to smaller coil B, then

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a

Magnetic field at O due to larger coil is 33B0

b

Magnetic field at O due to larger coil is B0

c

Net magnetic field at O is 2B0

d

Net magnetic field at O is zero

answer is B.

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Detailed Solution

Due to smaller coil  B0=μ04π2I(πR2)N(R2+x2)3/2Due to larger coil B'=μ04π2I(9πR2)3N[(3R)2+(3x)2]3/2=2727B0=B0
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