Questions

Two circular coils of radii 5 cm and 10 cm carry equal currents of 2 A. The coils have 50 and 100 turns, respectively and are placed in such a way that their planes as well as their centers coincide. Magnitude of magnetic field at the common center of coils is

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8π×10−4 T, if current in the coils are in same sense

4π×10−4 T, if current in the coils are in opposite sense

zero, if current in the coils are in opposite sense

8π×10−4 T, if current in the coils are in opposite sense

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detailed solution

Correct option is A

Using B=μ0NI2R B→1=B→2=4π×10−4 TIf current in same sense Bnet=8π×10−4 TIf current in opposite sense Bnet =0

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Similar Questions

A small coil C with N= 200 turns is mounted on one end of a balance beam and introduced between the poles of an electromagnet as shown in figure. The area of the coil is S = 1cm², the length of the right arm of the balance beam is I = 30 cm. When there is no current in the coil the balance is in equilibrium. On passing a current I = 22 mA through the coil, equilibrium is restored by putting an additional weight of mass m = 60 mg on the balance pan. Find the magnetic induction field (in terms of x 10^-1 T) between the poles of the electromagnet, assuming it to be uniform.