Two circular coils of radii 5 cm and 10 cm carry equal currents of 2 A. The coils have 50 and 100 turns, respectively and are placed in such a way that their planes as well as their centers coincide. Magnitude of magnetic field at the common center of coils is
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a
8π×10−4 T, if current in the coils are in same sense
b
4π×10−4 T, if current in the coils are in opposite sense
c
zero, if current in the coils are in opposite sense
d
8π×10−4 T, if current in the coils are in opposite sense
answer is A.
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Detailed Solution
Using B=μ0NI2R B→1=B→2=4π×10−4 TIf current in same sense Bnet=8π×10−4 TIf current in opposite sense Bnet =0