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Q.

Two circular discs are of same thickness. The diameter of A is twice that of B. The moment of inertia of A as compared to that of B is

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a

twice as large

b

four times as large

c

eight times as large

d

16 times as large

answer is D.

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Detailed Solution

Mass of disc ∝ area M∝R2 ⇒ MA=4MB          as RA=2RBIAIB=12MARA212MBRB2=4MB×2RB2MB×RB2=16
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