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Q.

Two circular discs A and B are of equal masses and thicknesses but made of metal with densities dA and dB (dA > dB).If their moments of inertia about an axis passingthrough their centers and perpendicular to circular faces are IA and IB, then

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a

IA=IB

b

IA>IB

c

IA

d

IA≥IB

answer is C.

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Detailed Solution

Let M be the mass of each disc. Let RA and RB, be the radii of discs A and B, respectively. Then M=πRA2tdA=πRB2tdB As dA>dB, so RA2
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