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Two circular discs A and B of equal masses and thickness but made of metals with densities dA and dB dA>dB.If their moments of inertia about an axis through the centre and normal to the circular forces be IA and IB, then.

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a

IA =IB

b

IA > IB

c

IA < IB

d

IA≥IB

answer is C.

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Detailed Solution

IA=mArA22 and IB=mBrB22∴ IAIB=rA2rB2 ∵ mA=mB………………(1)Now, mA=πrA2tdAmB=πrB2tdBSo, πrA2tdA=πrB2tdBOr rA2rB2=dBdA……………………..(2)IAIB=dBdAAs dA>dB hence IA

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