Two circular discs A and B of equal masses and thicknesses but are made of metals with densities dA and dB(dA > dB). If their moments of inertia about an axis passing through the centre and normal to the circular faces be IA and IB, then
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a
IA = IB
b
IA > IB
c
IA < IB
d
IA ≥ IB
answer is C.
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Detailed Solution
mass = volume ×density ⇒ M = (πR2t)d ------(1)where t is thicknessI = MR22------(2)From (1) and (2), we getI = M2 2πdt ⇒ I ∝ 1d ⇒ IA < IB