First slide

Moment of intertia

Question

Two circular rings of equal mass M, and radius R are placed touching each other. The moment of inertia of the system about tangential axis in the plane of system passing through point of contact of rings is

Moderate

A

3 MR²
B

3/2 MR²
C

6 MR²
D

5/2 MR²

Solution

$\large I_1=\frac 12.MR^2$
By parallel axis Theorem
$\large I_2=2\left ( I_1+MR^2 \right )=2\left ( \frac {MR^2}{2}+MR^2 \right )$
$\large \Rightarrow I_2=3MR^2$

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