Two closed containers of equal volume of air are initially at 1.05×105 Pa and 300 K temperature. If the containers are connected by a narrow tube and one container is maintained at 300 K temperature and other at 400 K temperature. The final pressure (in kPa) in the containers is ______________kPa.

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answer is 120.

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Detailed Solution

Final pressure in both the containers remain same as they are connected. If initial pressure volume and temperatures of the two containers are denoted by P0V0 and T0 and Pf,V0T2 and PfV0T2, are the final pressure volume and temperature in the two containers then according to gas law and constant number of moles, we have P02V0T0=PfV0T1+PfV0T2or Pf=2P0T0×T1T2T1+T2Here it is given that P0=105KPa,T0=300K,T1=300K, T2=400K, then we get Pf=2×105×103×400300+400=120kPa

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