Questions
Two closed organ pipes, when sounded simultaneously gave 4 beats per sec. If longer pipe has a length of 1m. Then length of shorter pipe will be, (v = 300 m/s)
detailed solution
Correct option is B
For first pipe n1=v4l1 and for second pipe n2=v4l2So, number of beats = n2−n1=4⇒4=v41l2−1l1⇒16=3001l2−11⇒l2=94.9cmTalk to our academic expert!
Similar Questions
A tube of certain diameter and of length 48 cm is open at both ends. Its fundamental frequency of resonance is found to be 320 Hz. The velocity of sound in air is 320 m/s. One end of the tube is now closed, considering the effect of end correction, calculate the lowest frequency of resonance for the tube (in Hz).
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