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Q.

Two closed organ pipes, when sounded simultaneously gave 4 beats per sec. If longer pipe has a length of 1m. Then length of shorter pipe will be, (v = 300 m/s)

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a

185.5 cm

b

94.9 cm

c

90 cm

d

80 cm

answer is B.

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Detailed Solution

For first pipe n1=v4l1 and for second pipe n2=v4l2So, number of beats = n2−n1=4⇒4=v41l2−1l1⇒16=3001l2−11⇒l2=94.9cm
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