First slide

Young's double slit Experiment

Question

Two coherent monochromatic light beams of intensities I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam are

Moderate

A

5I and I
B

5I and 3I
C

9I and I
D

9I and 3I

Solution

$I_{max} = {(\sqrt{I_{1}} + \sqrt{I_{2}})}^{2} = (\sqrt{I} + \sqrt{4 I})^{2} = 9 I$
$I_{min} = {(\sqrt{I_{1}} - \sqrt{I_{2}})}^{2} = (\sqrt{I} - \sqrt{4 I})^{2} = I$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App