First slide

In YDSE one of the slits is covered with a thin transparent sheet

Question

Two coherent sources of equal intensity produce maximum intensity of 100 units at a point. If the intensity of one of the sources is reduced by 36% reducing its width, then the intensity of light at the same point will be

Moderate

A

90
B

89
C

67
D

81

Solution

Intensity of each source $I_{0} = \frac{100}{4} = 25 unit$
If the intensity of one of the source is reduced by 36% then I1 = 25 unit and
$I_{2} = 25 - 25 \times \frac{36}{100} = 16 (unit)$
Hence resultant intensity at the same point will be
$I = I_{1} + I_{2} + 2 \sqrt{I_{1} I_{2}} = 25 + 16 + 2 \sqrt{25 \times 16} = 81 unit$

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