Questions
Two coherent sources of sound, and , produce sound waves of the same wavelength, m, in phase. and are placed 1.5 m apart (see fig). A listener, located at L, directly in front of finds that the intensity is at a minimum when he is 2 m away from . The listener moves away from , keeping his distance from fixed. The adjacent maximum of intensity is observed when the listener is at a distance d from . Then, d is :
detailed solution
Correct option is B
At L:Phase difference=Δϕ=2πλ△x=2πλS1L−S2L⇒Δϕ=2π14+94−2=2π52−2=πThis means Minima is formed. Now at other position, Δϕ=2π1d−2=2π for adjacent maxima Δϕ=2π ⇒d=3mTalk to our academic expert!
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Two waves are propagating to the point P along a straight line produced by two sources A and B of simple harmonic and of equal frequency. The amplitude of every wave at P is ‘a’ and the phase of A is ahead by than that of B and the distance AP is greater than BP by 50 cm. Then the resultant amplitude at the point P will be, if the wavelength is 1 meter
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