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Q.

Two coils have a mutual inductance 0.005 H. The current changes in first coil according to equation I=I0 sin wt where I0 = 2 A and ω=100π rad/sec. The maximum value of emf in second coil is :

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a

4π

b

3π

c

2π

d

π

answer is D.

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Detailed Solution

e=MdIdt=0.005 x ddtI0 sinωt   =0.005 I0 ω cosωt ⇒emax=0.005 x 2 x 100π=π
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