Two coils have their mutual inductance 0.005 H. The current changes in the first coil according to equation i = 10 sin 100πt A. The maximum value of emf in the second coil in volt, is
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a
5
b
5π
c
0.5π
d
π
answer is B.
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Detailed Solution
didt=1000πcos100πt A/s⇒didtmax=1000π A/s∴ εmax=Ldidtmax=5×10-3×1000π volt=5π volt.