Two coils of $$self-inductances$$ $$2$$ mH and $$8$$ mH are placed so close together that the effective flux in one coil is completely linked with the other. The mutual inductance between these coils is

Question

Infinity Learn · Accepted Answer

When the total flux associated with one coil links with the other, i.e., a case of maximum flux linkage, then $$M12=N2$$ϕ$$B2i1$$ and  $$M21=N1$$ϕ$$B1i2Similarly$$, $$L1=N1$$ϕ$$B1i1$$ and $$L2=N2$$ϕ$$B2i2$$ If all the flux of coil $$2$$ links coil I and vice versa, then Since, $$M12$$ $$=$$ $$M21$$ $$=$$ M, hence we have $$M12M21=M2=N1N2$$ϕ$$B1$$ϕ$$B2i1i2=L1L2$$ $$Mmax=L1L2Given$$,  $$L1=2mH$$,$$L2=8mHMmax=2$$×$$8=16=4mH$$

Two coils of self-inductances 2 mH and 8 mH are placed so close together that the effective flux in one coil is completely linked with the other. The mutual inductance between these coils is

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