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Two communicating vessels contain mercury. The diameter of one vessel is n times larger than the diameter of the other. A column of water of height h is poured into the left vessel. The mercury level will rise in the right-hand vessel   (s = relative density of mercury and  ρ = density of water) by

a
n2h(n+1)2s
b
h(n2+1) s
c
h(n+1)2s
d
hn2s

detailed solution

Correct option is B

If the level in narrow tube goes down by h1 then in wider tube goes up to h2, Now,  πr2h1=π(nr)2h2⇒h1=n2h2Now, pressure at point A = pressure at point Bhρg=(h1+h2)ρ'g⇒h=n2h2+h2s⁡ As s=ρ′ρ ⇒h2=hn2+1s

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