First slide
Magnetic field due to a moving charge
Question

Two concentric coils, each of radius equal to 2π cm, are placed at right angles to each other. Currents of 3A and 4 A, respectively, are flowing through the two coils. The magnetic induction, in Wb m-2, at the center of the coils will be  

[μ0 = 4π × 10-7 Wb(Am-1)]

Easy
Solution

As the coils are placed perpendicular to each other so their magnetic fields will also be perpendicular to each other.

Bnet=B12+B22 B1=μ0×32.2π×10-2 , B2=μ0×42.2π×10-2

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