Two concentric coplanar circular loops made of wire with resistance per unit length 10−4Ω/m, have diameters 0.2 m and 2 m. A time varying potential difference (4 + 2.5t) volt is applied to the larger loop. The current (in A) in the smaller loop is _________________.
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
answer is 1.25.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
The situation described in question is shown in figureThe magnetic induction at O, due to the current in large loop is given as where B0=μ0i2R⇒ i=VR=(4+2.5t)(2πR)ρ⇒ B0=μ02R(4+2.5t)(2πR)ρHere we consider that the central loop is very small i.e., r << R, so the field may be considered as constant within the loop. Thus within the loop the field is B0 so the flux through smaller loop is given asϕ=B0×πr2=μ02R(4+2.5t)(2πR)ρ⋅πr2Induced emf in the smaller loop is given ase=dϕdt=μ0r24R2ρ×(2.5)Thus current i in the smaller loop is given asi=eR=μ0r24R2ρ×2.5×12πrρ⇒ i=2.5μ0r8πR2ρ2⇒i=2.5×4π×10−7(0.1)8π×1×10−8=1.25A