First slide

Ohm's law

Question

Two conductors, both having same length and same area of cross-section are joined in series. Their materials are different and resistivity of one of them is $ρ$ . If equivalent resistivity of their combination is 3 $ρ$ , resistivity of the other conductor is :

Easy

A

$ρ$
B

2 $ρ$
C

4 $ρ$
D

5 $ρ$

Solution

$R_{eq} = R_{1} + R_{2} \Rightarrow \frac{(3 ρ) (2 l)}{A} = \frac{ρl}{A} + \frac{ρ_{1} l}{A} \Rightarrow ρ_{1} = 5 ρ$

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