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Two conductors, both having same length and same area of cross-section are joined in series. Their materials are different and resistivity of one of them is ρ. If equivalent resistivity of their combination is 3 ρ, resistivity of the other conductor is :

a
ρ
b
2 ρ
c
4 ρ
d
5 ρ

detailed solution

Correct option is D

Req=R1+R2⇒3ρ2lA=ρlA+ρ1lA⇒ρ1=5 ρ

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