Two conductors, both having same length and same area of cross-section are joined in series. Their materials are different and resistivity of one of them is ρ. If equivalent resistivity of their combination is 3 ρ, resistivity of the other conductor is :

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2 ρ

4 ρ

5 ρ

answer is D.

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Detailed Solution

Req=R1+R2⇒3ρ2lA=ρlA+ρ1lA⇒ρ1=5 ρ

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