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Q.

Two conductors having thicknesses d1 and d2 , thermal conductivities K1 and K2 are placed one above the other. The equivalent thermal conductance is:

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a

d1+d2K2d2+K2d12K1+K2

b

(d1-d2)(K1d2+K2d1)1(K1+K2)

c

K1K2(d1+d2)d1K2+d2K1

d

none of the above

answer is C.

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Detailed Solution

Here,        d1+d2kA=d1K1A+d2K2A So,             K=K1K2(d1+d2)d1K2+d2K1
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