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Q.

Two constant forces F→1 and F→2 act on a body of mass 8 kg. These forces displace the body from point P (1, -2, 3) to Q (2, 3, 7) in 2s starting from rest. Force F→1 is of magnitude 9 N and is acting along vector (2i^−2j^+k^). Work done by the force F→2 is

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a

80 J

b

-80 J

c

-180 J

d

180 J

answer is D.

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Detailed Solution

s→=i^+5j^+4k^=12F→1+F→2m(2)2   ...........(i)F→1=9(2i^−2j^+k^)22+22+1=6i^−6j^+3k^    ...........(ii)From Eqs.(i) and (ii), F2→=-2i^+26j^+13k^)Work done by F→2:W=F→2⋅s→⋅=180J
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