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Q.

Two containers of equal volume contain identical gases at pressures P1 and P2 and absolute temperatures T1 and T2 respectively. The vessels are joined and the gas reaches a common pressure P and a common temperature T. Then

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a

P=P1T1+P2T2T

b

P=12P1T1+P2T2T

c

P=P1T2+P2T1T12+T22T

d

P=P1T2+P2T1T12−T22T

answer is B.

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Detailed Solution

Since P1V = n1RT1and P2V = n2RT2After joining the vessels we have P(2V)=n1+n2RT⇒P(2V)=P1VRT1+P2VRT2RT⇒P=12P1T1+P2T2T
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