Two convex lenses of focal lengths 20 cm and 30 cm are kept at a separation of 15 cm. Then power of the combination is

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6.12 D

2.13 D

5.83 D

4.5 D

answer is C.

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Detailed Solution

Equivalent focal length F is give by 1F=1f1+1f2−df1f2=120+130−1520×30am−1⇒ Power P=100FD=10020+10030−15×10020×30D=5.83 D

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