Two cubical blocks identical in dimension float in water in such a way that 1st block floats with half part immersed in water and second block floats with 34th of its volume inside the water the ratio of densities of blocks is
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a
2:3
b
3:4
c
1:3
d
1:4
answer is A.
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Detailed Solution
Given Weight of block in water =Weight of block in airv2ρ2g=v1ρ1g (∵w=mg∵m=ρv) Given v2=34v , v1=12v ⇒34v×ρ2×g=12v×ρ1×g ⇒ρ2ρ1=23