Two cylinders A and I [Fig. (2)] of the same material have same length, their radii being in the ratio 1 : 2,respectively. The upper end of A is rigidly fixed. The lower end of B is twisted through an angle 0. The angle of twist of the cylinder A is

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1516θ

1615θ

1617θ

1716θ

answer is C.

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Detailed Solution

Let θ′be the angle of twist for cylinder A.For A, τ=πηr42lθ′……………(1)For B τ=πη(2r)42l×θ−θ′….(2)From eqs. (1) and (2),θ′=16θ−θ′ or 17θ′=16θ∴ θ′=1617θ

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