Q.

Two cylindrical rods of uniform cross-sectional area A and 2A, having free electrons per unit volume 2n and n respectively are joined in series. A current I flows through them in steady state. Then the ratio of drift velocity of free electrons vL in left rod to drift velocity of electrons in the right rod vR is

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a

12

b

1

c

2

d

4

answer is B.

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Detailed Solution

Since current I = neAvd through both rods is same,∴    2neAvL =  ne2A vR or  vLvR=1
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