Two cylindrical rods of uniform cross-sectional area A and 2A, having free electrons per unit volume 2n and n respectively are joined in series. A current I flows through them in steady state. Then the ratio of drift velocity of free electrons vL in left rod to drift velocity of electrons in the right rod vR is
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a
12
b
1
c
2
d
4
answer is B.
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Detailed Solution
Since current I = neAvd through both rods is same,∴ 2neAvL = ne2A vR or vLvR=1