First slide
Inductance
Question

Two different coils have self-inductance  L1=8mH, L2=2mH . The current in one coil is increased at a constant rate. The current in the second coil is also increased at the same rate. At a certain instant of time, the power given to the two coils is the same. At that time the current, the induced voltage and the energy stored in the first coil are i1,V1 and W1 respectively. Corresponding values for the second coil at the same instant are i2,V2  and W2 respectively. Then

Moderate
Solution

From Faraday’s Law, the induced voltage   VL
rate of change of current is constant   V=Ldidt
V2V1=L2L1=28=14V1V2=4
Power given to the two coils is same, i.e., 
V1i1=V2i2i1i2=V2V1=14
Energy stored  W=12Li2
W2W1=L2L1i2i12=14(4)2=4W1W2=14

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