Two different masses are connected to two light and inextensible strings as shown in the figure. Both masses rotate about a central fixed point with constant angular speed of 10 rad s-1 on a smooth horizontal plane. Find the ratio of tensions T1/T2 in the strings.  (Given: M1=0.25kg,M2=1.0kg,R1=5cm,R2=10cm )

Both the masses are moving in horizontal plane with same angular speed 10 rad/s. Here forces in radial direction can be tensions only. For M2:Fnet =T2=M2a2 F.B.D. of M2:⇒T2=M2ω2R2   ………(i) For M1:T1−T2=M1a1 F.B.D. of M1:⇒T1=M1a1+T2T1=M1ω2R1+M2ω2R2  ……….(ii)Dividing equation (ii) from (i), we get ∴ T1T2=M1R1+M2R2M2R2                =M1M2×R1R2+1=0.251×510+1⇒ T1T2=98Here centripetal force on M2 is T2 and on M1 is T1 - T2.