Two different wires having length L1 and L2 and respective temperature coefficient of linear expansion α1 and α2,are joined end-to-end. Then the effective temperature coefficient of linear expansion is:

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α1+α22

2α1α2

4α1α2α1+α2L2L1L2+L12

α1L1+α2L2L1+L2

answer is D.

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Detailed Solution

Thermal expansion for effective wireLeffαeffΔθ=L1α1Δθ+L2α2Δθ⇒αeff=L1α1+L2α2L1+L2

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