Questions

# Two different wires having length ${L}_{1}$  and  ${L}_{2}$ and respective temperature coefficient of linear expansion ${\alpha }_{1}$  and  ${\alpha }_{2}$,are joined end-to-end. Then the effective temperature coefficient of linear expansion is:

## Unlock the full solution & master the concept.

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya
a
α1+α22
b
2α1α2
c
4α1α2α1+α2L2L1L2+L12
d
α1L1+α2L2L1+L2
NEW

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is D

Thermal  expansion for effective wireLeffαeffΔθ=L1α1Δθ+L2α2Δθ​⇒αeff=L1α1+L2α2L1+L2

Similar Questions

The coefficient of linear expansion of brass and steel are ${\mathrm{\alpha }}_{1}$ and ${\alpha }_{2}$. If we take a brass rod of length ${l}_{1}$ and steel rod of length ${l}_{\mathit{2}}$ at 0oC, their difference in length $\left({l}_{2}-{l}_{1}\right)$will remain the same at all temperatures if

Get your all doubts cleared from
Sri Chaitanya experts

+91