Q.
Two disc are suspended with a ribbon between them as shown in figure. At t = 0 the ribbon has 100 complete anti-clock twists in it, i.e., the ribbon is twisted by keeping the upper disc fixed and rotating the lower disc anti-clock when viewed from above. At t = 0 the upper disc starts to rotate at ωu=2rpm anticlockwise, and the lower disc, starting from rest, begins to rotate with a clockwise angular acceleration of a magnitude of 1 rpm/s2.At what time tf does the ribbon becomes momentarily untwisted?
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a
107 sec
b
117 sec
c
97 sec
d
127 sec
answer is A.
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Detailed Solution
Both disc rotate in such a way that ribbon is untwisted. i.e., the upper disc will rotates at constant angular speed (approximately) and lower disc will rotates at constant angular acceleration (approximately). Angles rotated by upper disc = θu = ωutf Lower disc = θL = ωLtf +12aL tf2i.e., relative angular displacement ; (100)2π = 22π60 tf + 12 (2π60) tf2tf = 107.56 sec.Angles rotated by upper disc = θu=260×107.56θu=3.585rev Angle rotated by lower disc = θL=12αLtf2= 12160×(107.56)2 = 96.407Relative number of turns = 3.585 + 96.407 = 99.99≈100rev
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