Questions
Two discs of same moment of inertia rotating about their respective geometrical axis passing through centre and perpendicular to the plane of disc with angular velocities . They are brought into contact face to face coinciding the axis of rotation. The expression for loss of energy during this process is
detailed solution
Correct option is A
Common angular veocity ω is given , Iω1 + Iω2 = 2Iω ⇒ ω = ω1+ω22(K.E.)i = 12Iω12+12Iω22(K.E.)f = 12×(2I)ω2 = I(ω1+ω22)2Loss in K.E. = (K.E.)i-(K.E.)f = I4(ω1-ω2)2Similar Questions
A uniform thin rod of length l and mass m is hinged at a distance l/4 from one of the end and released from horizontal position as shown in Fig. The angular velocity of the rod as it passes the vertical position is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests