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Two electric charges 12μC and 6μC are placed 20 cm apart in air. There will be a point P on the line joining these charges and outside the region between them, at which the electric potential is zero. The distance of P from 6μC charge is 

a
0.10 m
b
0.15 m
c
0.20 m
d
0.25 m

detailed solution

Correct option is C

Point P will lie near the charge which is smaller in magnitude i.e. −6μC. Hence potential at PV=14πε0−6×10−6x+14πε012×10−6(0.2+x)=0⇒x=0.2m

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