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Q.

Two electric charges 12μC and −6μC are placed 20 cm apart in air. There will be a point P on the line joining these charges and outside the region between them, at which the electric potential is zero. The distance of P from −6μC charge is

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a

0.10 m

b

0.15 m

c

0.20 m

d

0.25 m

answer is C.

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Detailed Solution

Point P will lie near the charge which is smaller in magnitude i.e. −6μC. Hence potential at PV=14πε0−6×10−6x+14πε012×10−6(0.2+x)=0⇒x=0.2m
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Two electric charges 12μC and −6μC are placed 20 cm apart in air. There will be a point P on the line joining these charges and outside the region between them, at which the electric potential is zero. The distance of P from −6μC charge is