First slide

Potential energy

Question

Two electric charges 12 μC and-6 μCare placed 20 cm apart in air. There will be a point P on the line joining these charges and outside the region between them, at which the electric potential is zero. The distance of P from -6 μC charge is

Moderate

A

0.10 m
B

0.15 m
C

0.20 m
D

0.25 m

Solution

Point P will lie near the charge which is smaller in magnitude i.e., - 6 μC. Hence, potential at P
$V = \frac{1}{4 {πε}_{0}} \frac{(- 6 \times 10^{- 6})}{x} + \frac{1}{4 {πε}_{0}} \frac{(12 \times 10^{- 6})}{(0.2 + x)} = 0 \Rightarrow x = 0.2 m$

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