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Questions  

Two electric charges 12 μC and-6 μCare placed 20 cm apart in air. There will be a point P on the line joining these charges and outside the region between them, at which the electric potential is zero. The distance of P from -6 μC charge is

a
0.10 m
b
0.15 m
c
0.20 m
d
0.25 m

detailed solution

Correct option is C

Point P will lie near the charge which is smaller in magnitude i.e., - 6 μC. Hence, potential at PV=14πε0-6×10-6x+14πε012×10-6(0.2+x)=0⇒  x=0.2 m

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