Questions
Two electric lamps of 40 watt each are connected in parallel. The power consumed by the combination will be
detailed solution
Correct option is C
P1=V2R1 and P2=V2R2When bulbs are connected in parallel, then equivalent resistance R is given by Rp=R1R2R1+R2∴ Pp=V2R1R2R1+R2=V2R1+R2R1R2=V2V2/P1+V2/P2V2/P1×V2/P2=V4P1+P2P1P2V41/P1P2=P1+P2=40+40=80 watt Note. For series combinationPs=V2R1+R2=V2V2/P1+V2/P2=P1P2P1+P2Talk to our academic expert!
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A resistor R is connected across a battery of emf 12 V. It observed that terminal potential differenceis 9 V and the power delivered to resistor is 18 W. Internal resistance of the battery ‘r’ and the resistance R are respectively
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