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Questions  

Two ends of a current carrying wire AB of length l, radius r and resistivity of material ρ are connected to the terminals of a battery of emf E. The wire AB is placed in a uniform magnetic field of induction B as shown. Force experienced by the wire is 20 N. It radius of the wire is doubled and length also doubled, force experienced by the wire will be 

a
10 N
b
40 N
c
80 N
d
60 N

detailed solution

Correct option is C

Current through the wire is given by i=ER=Eρ.l/πr2=E.πr2ρ.l⇒i∝r2lF=Bil∴F ∝r2 F1F=r1r2⇒F1=4×20  N=80  N

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Two infinitely current carrying insulated wires AB and CD are carrying same current  I. The wires cross each other at right angles as shown in figure. Three identical conductors P1Q1 , P2Q2 and P3Q3, carrying same current are placed a shown in figure and the forces acting on them are F1 , F2 and F3 respectively. Then select the correct option.


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